📖 generic · CBSE Class 10 ENGLISH MEDIUM · MATHEMATICS · Page 1grammar_exercise

2.1 Introduction · Part 8

Chapter 2: POLYNOMIALS · MATHEMATICS

) = x + x – . By the method of splitting the middle term, x + x – = x + x – x – = x ( x + ) – ( x + ) = ( x – )( x + ) Hence, the value of x + x – is zero when either x – = or x + = , i.e., when x = or x = – . So, the zeroes of x + x – are and – . Observe that : Sum of its zeroes ) Product of its zeroes = In general, if  * and  * are the zeroes of the quadratic polynomial p ( x ) = ax + bx + c , a  , then you know that x –  and x –  are the factors of p ( x ).

Therefore, ax + bx + c = k ( x –  ) ( x –  ), where k is a constant = k [ x – (  +  ) x +  ] = kx – k (  +  ) x + k  Comparing the coefficients of x , x and constant terms on both the sides, we get a = k , b = – k (  +  ) and c = k  This gives  +  = –b a ,  = c *  ,  are Greek letters pronounced as ‘alpha’ and ‘beta’ respectively. We will use later one more letter ‘  ’ pronounced as ‘gamma’. i.e., sum of zeroes =  +  = ) product of zeroes =  = c Let us consider some examples. Example : Find the zeroes of the quadratic polynomial x + x + , and verify the relationship between the zeroes and the coefficients.

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