→ ( ) × 3e – 1e – K Cr O + 6KI → H SO K SO Cr SO ( ) I H O K Cr O KI H SO K Cr O KI → → K SO H O Cr Cr (SO ) +3I 7H SO 4K SO ( ) SO I + 7H O 11th Std Chemistry 11th Std Chemistry - - - - (ii) KMnO Na S O MnO Na S O KOH → 3e – 2e – ⇒ → ⇒ → 2KMnO + 3Na SO 2MnO + MnO Na SO KOH KMnO Na SO Na SO + KOH ⇒ → KMnO Na SO MnO Na SO H O 2KOH (iii) 2e – 1e – Cu HNO C u NO N o H O → ( ) Cu + 2HNO 2HNO 2NO → → Cu NO NO H O Cu HNO Cu NO ( ) ( ) H O Cu HNO Cu NO NO H O → ( ) (iv) 5e – 1e – × KMnO H C O H SO K SO MnSO CO H O → 2KMnO + 5H C O + → H SO K SO MnSO CO H O KMnO H C O H SO K SO H O KMnO H C O H SO K SO → → 2MnSO +10CO MnSO CO H O 11th Std Chemistry 11th Std Chemistry - - - - . (i) Half reaction are MnO Mn Sn Sn → → ............. ( ) and ............. ( ) ( ) ( ) MnO H e Mn H O Sn Sn e MnO H e Mn H O Sn Sn 0e ⇒ → MnO Sn H
📖 Samacheer Kalvi · 11th TN - English Medium · Chemistry Volume 1 · Page 246question
Unit - 1 Basic Concepts of Chemistry and Chemical Calculations · Part 10
Chapter 3: 7 · Chemistry Volume 1
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