📖 Samacheer Kalvi · 11th TN - English Medium · Chemistry Volume 1 · Page 278question

Unit - 6 Gaseous State · Part 2

Chapter 3: 7 · Chemistry Volume 1

mol mol L L mol O H H e e 11th Std Chemistry 11th Std Chemistry - - - - P total ×V total = atm × . l ∴ ∴ P atm l l P atm at total total atm P O m P He = x He × P total x x P He He O He He He ∴ . atm P atm He = . (b) 2KClO (s) 2KCl (s) + 3O (g) P total = mm Hg P H2O = .

mm Hg P P P P P P total O H O O total H O ∴ P = . mm Hg T = K T = K P = ? P P P P mm Hg K K P mm Hg P O ⇒ =       ∴ mm Hg ) t = . minutes (gas) hydro carbon t = .

minutes (gas) Bromine γ γ Hydrocarbon Bro e Bro e Hydrocarbon t t Volume is cons min min ( tan  t utes utes ) min . min γ γ Hydrocarbon Bro e Bro e hydrocarbon M M gmol M min min hydro carbon Squaring on both sides and rearranging, M g mol hydro carbon = ( . ) M hydro carbon = . g mol – n( ) + (2n+ ) = 12n + 2n + = general formula for hydrocarbon C H (alkane) 14n = – 14n = n = ∴ The hydro carbon is C H ( )+ = CH ) Critical temperature of a gas is defined as the temperature above which it

Related topics

Have a question about this topic?

Get an AI answer grounded in your actual textbook — with the exact page reference.

Ask AI about this topic →