📖 Samacheer Kalvi · 11th TN - English Medium · Chemistry Volume 1 · Page 278question

Unit - 6 Gaseous State · Part 6

Chapter 3: 7 · Chemistry Volume 1

= atm V = . ml T = C + = K P = atm V = ? P V P V P V P atm ml K K atm . ml .

Given, V = . x - dm , P = mm of Hg T = K m = ? PV RT mm Hg . − L mm Hg L K mol - - K Molar mass mol Mass Molar mass Mass .

g = .1mg . unknown N N unknown N unknown t t M M g mol sec sec M M gmol unknown unknown sec . sec M g mol - unknown On squaring both sides and rearranging g mol sec sec M unknown 11th Std Chemistry 11th Std Chemistry - - - - . m O2 = .

g P O2 = ? m CO2 = . g P CO2 = ? T = K P = .

atm P O2 = X O2 x Total Pressure X O O2 O2 CO2 O2 Mass of O Molar mass of O . g g mol mol Mass of O Molar mass of O − = CO2 C C g g mol mol X O O2 O2 CO2 X P X CO O O CO2 O2 CO2 = . Total pressure atm atm P CO = . X atm CO × Total pressure atm .

Pressure of the gas in the tank at its melting point = K P atom T K P ; ; ; ? P P P P ⇒ = . atm K K atm At K the pressure of

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