📖 Samacheer Kalvi · 11th TN - English Medium · Chemistry Volume 1 · Page 285question

Unit - 7 Thermodynamics · Part 6

Chapter 3: 7 · Chemistry Volume 1

= l . – 3x = 3x = . l x = . l Given mixture contains .

lit of methane and . lit of propane, hence H H H CH lit x lit H C H lit C C C ( ) ( ) ( ) x lit H kJ mol lit C lit lit lit H C kJ mol kJ mol – . KJ mol – C . 4E C–H = kJ mol – E C–H = kJ mol – E C–C + E C–H = kJ mol – E C–C + × = kJ mol – E C–C + = kJ mol – E C–C = kJ mol – .

During compression, energy of the system increases, in isothermal ­condition, to main- tain temperature constant, heat is liberated from the system. Hence q is negative. During compression entropy decreases. During compression work is don e on the system, hence w is positive .

∆ = ∆ = ∆ ∆ S H H S J mol J mol K K C b b 11th Std Chemistry 11th Std Chemistry - - - - . In CaCO (S) → CaO(S) + CO (g), entropy change is positive. in option d, A solid reactant gives a gaseous product. Hence the entropy change is expected to be maximum for this process.

. D G = D H – T D S At 300K D G = 30000 J mol – – K × J K – mol – D G = above K ; ∆G will be negative and reaction becomes spontaneous. I Keys to the short answer questions: . SOLUTION : Given : n = moles V i = ml = .

lit V f = lit T = C = K w = − . nRTlog V

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