11th Std Chemistry 11th Std Chemistry - - - - ∆ = + S J mol K 35200 ΔS V = + . J K − mol − . Solution : Given : ΔH = . kJ mol − = 30560 J mol − ΔS = .
× - kJK − mol − T = ? at which ΔG= ΔG = ΔH − TΔS = ΔH − TΔS H S = ∆ ∆ kJmol kJK mol . × - T = K (i) At 4589K ; ΔG = the reaction is in equilibrium. (ii) at temperature below K , ΔH > T Δ S ΔG = ΔH − T Δ S > , the reaction in the forward direction, is non spontaneous.
In other words the reaction occurs in the backward direction. . Solution : Given T = 400K ; ΔH = . kJ mol − =77200 J mol − ; ΔS = JK − mol − ΔG = − .
RT log K eq log K G RT eq = – ∆ log K H T S RT eq = − ∆ −∆