Exercise 3.8
Chapter 3: Chapter 4 · Knowledge Base · EN medium
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( )( i ) θ = − π ; θ = nπ + ( − ) n − π . n ∈ Z ( ii ) θ = π ; θ = nπ + π , n ∈ Z ( iii ) θ = − π ; θ = nπ + − π , n ∈ Z ( )( i ) x = , π , π, π ( ii ) x = π , π , π ( iii ) x = π , π , π ( iv ) x = , π ( )( i ) x = ( n + ) π or x = nπ + ( − ) n π , n ∈ Z ( ii ) θ = nπ + ( − ) n π or θ = nπ + ( − ) n π n ∈ Z ( iii ) θ = ( n + ) π or θ = nπ, n ∈ Z ( iv ) θ = nπ or θ = nπ ± π , n ∈ Z ( v ) θ = nπ or θ = nπ + − π , n ∈ Z ( vi ) θ = ( n + ) π , n ∈ Z ( vii ) θ = nπ + π ± π , n ∈ Z ( viii ) θ = nπ − π ± π , n ∈ Z ( ix ) θ = nπ + π , n ∈ Z ( x ) θ = nπ ± π , n ∈ Z ( xi ) x = nπ ± π n ∈ Z Exercise .
📖 Namma Kalvi 11th Maths Textbook Volume 1 English Medium · Page 302
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( )( i ) θ = − π ; θ = nπ + ( − ) n − π . n ∈ Z ( ii ) θ = π ; θ = nπ + π , n ∈ Z ( iii ) θ = − π ; θ = nπ + − π , n ∈ Z ( )( i ) x = , π , π, π ( ii ) x = π , π , π ( iii ) x = π , π , π ( iv ) x = , π ( )( i ) x = ( n + ) π or x = nπ + ( − ) n π , n ∈ Z ( ii ) θ = nπ + ( − ) n π or θ = nπ + ( − ) n π n ∈ Z ( iii ) θ = ( n + ) π or θ = nπ, n ∈ Z ( iv ) θ = nπ or θ = nπ ± π , n ∈ Z ( v ) θ = nπ or θ = nπ + − π , n ∈ Z ( vi ) θ = ( n + ) π , n ∈ Z ( vii ) θ = nπ + π ± π , n ∈ Z ( viii ) θ = nπ − π ± π , n ∈ Z ( ix ) θ = nπ + π , n ∈ Z ( x ) θ = nπ ± π , n ∈ Z ( xi ) x = nπ ± π n ∈ Z Exercise .
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