BINOMIAL THEOREM
Chapter 2: 4 P 2 = 4 C 2 ××××× 2! or ( · MATHEMATICS · EN medium
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BINOMIAL THEOREM We now arrange the coefficients in these expansions as follows (Fig . ): Do we observe any pattern in this table that will help us to write the next row? Yes we do. It can be seen that the addition of ’s in the row for index gives rise to in the row for index . The addition of , and , in the row for index , gives rise to and in the row for index and so on. Also, is present at the beginning and at the end of each row. This can be continued till any index of our interest. We can extend the pattern given in Fig . by writing a few more rows.
📖 ncert books for class 11 maths cbsc · Page 170
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BINOMIAL THEOREM We now arrange the coefficients in these expansions as follows (Fig . ): Do we observe any pattern in this table that will help us to write the next row? Yes we do. It can be seen that the addition of ’s in the row for index gives rise to in the row for index .
The addition of , and , in the row for index , gives rise to and in the row for index and so on. Also, is present at the beginning and at the end of each row. This can be continued till any index of our interest. We can extend the pattern given in Fig .
by writing a few more rows.
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