📖 generic · CBSE Class 11 English medium · MATHEMATICS · Page 177question

Prove that ∑ · Part 6

Chapter 2: 4 P 2 = 4 C 2 ××××× 2! or ( · MATHEMATICS

r + ) BINOMIAL THEOREM or n – nr – n + r – = i.e., n – n ( r + ) + r – = Example Show that the coefficient of the middle term in the expansion of ( + x ) n is equal to the sum of the coefficients of two middle terms in the expansion of ( + x ) n – . Solution As n is even so the expansion ( + x ) n has only one middle term which is th  i.e., ( n + ) th term. The ( n + ) th term is n C n x n . The coefficient of x n is n C n Similarly, ( n – ) being odd, the other expansion has two middle terms, th n −+  and th n −+  i.e., n th and ( n + ) th terms.

The coefficients of these terms are n – C n – and n – C n , respectively. Now n – C n – + n – C n = n C n [As n C r – + n C r = n + C r ]. as required. Example Find the coefficient of a in the product ( + a ) ( – a ) using binomial theorem.

Solution We first expand each of the factors of the given product using Binomial Theorem. We have ( + a ) = C + C ( a ) + C ( a ) + C ( a ) + C ( a ) = + ( a ) + ( a ) + ( a ) + a . = +

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