. . cm OBSERVATIONS Zero error Zero correction (Z . C) = Zero error × LC Sl.No.
MSR × − m Vernier coincidence VSC (div) VSR = (VSC × LC) × − m TR = (MSR +VSR) × − m Diameter of the sphere = 2R correct reading = (TR ± Z.C) × − m Mean diameter 2R = . . . .
m Radius of the sphere R = . . . .
. . . m UNIT- (XI- - ) PRACTICAL FIRST UNIT- (XI- - ) PRACTICAL FIRST - - - - Practical CALCULATION Mass of the sphere M = .
kg (Known value is given ) Radius of the sphere R =. . . .
.metre Moment of inertia of a solid sphere about its diameter I d = MR = . . . .
. kg m RESULT The moment of inertia of the given solid sphere about its diameter using Vernier caliper I d = ………………….. kg m UNIT- (XI- - ) PRACTICAL FIRST UNIT- (XI- - ) PRACTICAL FIRST - - - - Practical