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WORK, ENERGY AND POWER

Chapter 5: WORK, ENERGY AND POWER · PHYSICS · EN medium

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= − ∫ kx x x m ( . ) This expression may also be obtained by considering the area of the triangle as in Fig. . (d). Note that the work done by the external pulling force F is positive since it overcomes the spring force. ( . ) Fig. . Illustration of the spring force with a block attached to the free end of the spring. (a) The spring force F s is zero when the displacement x from the equilibrium position is zero. (b) For the stretched spring x > and F s < (c) For the compressed spring x < and F s > .(d) The plot of F s versus x. The area of the shaded triangle represents the work done by the spring force. Due to the opposing signs of F s and x, this work done is negative, W kx / s .

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= − ∫ kx x x m ( . ) This expression may also be obtained by considering the area of the triangle as in Fig. . (d).

Note that the work done by the external pulling force F is positive since it overcomes the spring force. ( . ) Fig. .

Illustration of the spring force with a block attached to the free end of the spring. (a) The spring force F s is zero when the displacement x from the equilibrium position is zero. (b) For the stretched spring x > and F s < (c) For the compressed spring x < and F s > .(d) The plot of F s versus x. The area of the shaded triangle represents the work done by the spring force.

Due to the opposing signs of F s and x, this work done is negative, W kx / s . The same is true when the spring is compressed with a displacement x c (< ). The spring force does work / c s kx while the Fig. .

Parabolic plots of the potential energy V and kinetic energy K of a block attached to a spring obeying Hooke’s law. The two plots are complementary, one decreasing as the other increases. The total mechanical energy E = K + V remains constant. external force F does work + kx c / .

If the block is moved from an initial displacement x i to a final displacement x f , the work done by the spring force W s is k x x k x k x s ( . ) Thus the work done by the spring force depends only on the end points. Specifically, if the block is pulled from x i and allowed to return to x i ; k x x k x k x s = ( . ) The work done by the spring force in a cyclic process is zero.

We have explicitly demonstrated that the spring force (i) is position dependent only as first stated by Hooke, ( F s = − kx ); (ii) does work which only depends on the initial and final positions, e.g. Eq. ( . ).

Thus, the spring force is a conservative force . We define the potential energy V ( x ) of the spring to be zero when block and spring system is in the equilibrium position. For an extension (or compression) x the above analysis suggests that V(x) kx ( . ) You may easily verify that − d V/ d x = − k x , the spring force.

If the block of mass m in Fig. . is extended to x m and released from rest, then its total mechanical energy at any arbitrary point x , where x lies between – x m and + x m , will be given by where we have invoked the conservation of mechanical energy. This suggests that the speed and the kinetic energy will be maximum at the equilibrium position, x = , i.e., where v m is the maximum speed.

or Note that k/m has the dimensions of [T - ] and our equation is dimensionally correct. The kinetic energy gets converted to potential energy and vice versa, however, the total mechanical energy remains constant. This is graphically depicted in Fig. .

. Example . To simulate car accidents, auto manufacturers study the collisions of moving cars with mounted springs of different spring constants. Consider a typical simulation with a car of mass kg moving with a speed .

km/h on a smooth road and colliding with a horizontally mounted spring of spring constant . × N m – . What is the maximum compression of the spring ? Answer At maximum compression the kinetic energy of the car is converted entirely into the potential energy of the spring.

The kinetic energy of the moving car is mv = K = . × J where we have converted km h – to m s – [It is useful to remember that km h – = m s – ] . At maximum compression x m , the potential energy V of the spring is equal to the kinetic energy K of the moving car from the principle of conservation of mechanical energy. = .

× J We obtain x m = . m We note that we have idealised the situation. The spring is considered to be massless. The surface has been considered to possess negligible friction.

We conclude this section by making a few remarks on conservative forces. (i) Information on time is absent from the above discussions. In the example considered above, we can calculate the compression, but not the time over which the compression occurs. A solution of Newton’s Second Law for this system is required for temporal information.

(ii) Not all forces are conservative. Friction, for example, is a non-conservative force. The principle of conservation of energy will have to be modified in this case. This is illustrated in Example .

. (iii) The zero of the potential energy is arbitrary. It is set according to convenience. For the spring force we took V ( x ) = , at x = , i.e.

the unstretched spring had zero potential energy. For the constant gravitational force mg , we took V = on the earth’s surface. In a later chapter we shall see that for the force due to the universal law of gravitation, the zero is best defined at an infinite distance from the gravitational source. However, once the zero of the potential energy is fixed in a given discussion, it must be consistently adhered to throughout the discussion.

You cannot change horses in midstream ! Example . Consider Example . taking the coefficient of friction, µ , to be .

and calculate the maximum compression of the spring. Answer In presence of friction, both the spring force and the frictional force act so as to oppose the compression of the spring as shown in Fig. . .

We invoke the work-energy theorem, rather than the conservation of mechanical energy. The change in kinetic energy is Fig. . The forces acting on the car.

∆ K = K f − K i − The work done by the net force is kx m g x − µ Equating we have k x m g x + µ Now µ mg = . × × = × N (taking g = . m s - ). After rearranging the above equation we obtain the following quadratic equation in the unknown x m .

k x m g x µ where we take the positive square root since x m is positive. Putting in numerical values we obtain x m = . m which, as expected, is less than the result in Example . .

If the two forces on the body consist of a conservative force F c and a non-conservative force F nc , the conservation of mechanical energy formula will have to be modified. By the WE theorem ( F c + F nc ) ∆ x = ∆ K But F c ∆ x = − ∆ V Hence, ∆ ( K + V ) = F nc ∆ x ∆ E = F nc ∆ x where E is the total mechanical energy. Over the path this assumes the form

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