– , latent heat of fusion of ice = . × J kg – and latent heat of steam = . × J kg – . Answer We have Mass of the ice, m = kg specific heat capacity of ice, s ice = J kg – K – specific heat capacity of water, s water = J kg – K – latent heat of fusion of ice, L f ice = .
× J kg – latent heat of steam, L steam = . × J kg – Now, Q heat required to convert kg of ice at – ° C to steam at ° C, Q heat required to convert ice at – ° C to ice at ° C. m s ice ∆ T = ( kg) ( J kg – . K – ) [ –(– )] ° C = 75600 J Q heat required to melt ice at ° C to water at ° C m L f ice = ( kg) ( .
× J kg – ) 1005000 J Q heat required to convert water at ° C to water at ° C. ms w ∆ T = (3kg) (4186J kg – K – ) ( ° C) 1255800 J Q heat required to convert water at ° C to steam at ° C. m L steam = ( kg) ( . × J kg – ) 6768000 J So, Q Q + Q + Q + Q 75600J + 1005000 J + 1255800 J + 6768000 J .
× J . HEAT TRANSFER We have seen that heat is energy transfer from one system to another or from one part of a system to another part, arising due to temperature difference. What are the different ways by which this energy transfer takes place? There are three distinct modes of heat transfer: conduction, convection and radiation (Fig.