use the fact that at a steady state, heat given by an aluminium sphere will be equal to the heat absorbed by the water and calorimeter. Mass of aluminium sphere ( m ) = . kg Initial temperature of aluminium sphere = ° C Final temperature = ° C Change in temperature ( ∆ T )=( ° C- ° C)= ° C Let specific heat capacity of aluminium be s Al . Table .
Specific heat capacity of some substances at room temperature and atmospheric pressure Substance Specific heat capacity Substance Specific heat capacity (J kg – K – ) (J kg – K – ) Aluminium . Ice Carbon . Glass Copper . Iron Lead .
Kerosene Silver . Edible oil Tungesten . Mercury Water . The amount of heat lost by the aluminium sphere = × × ° .047kg C Al Al m s s Mass of water ( m ) = .
kg Mass of calorimeter ( m ) = . kg Initial temperature of water and calorimeter= ° C Final temperature of the mixture = ° C Change in temperature ( ∆ T ) = ° C – ° C = ° C Specific heat capacity of water ( s w ) = . × J kg – K – Specific heat capacity of copper calorimeter = . × J kg – K – The amount of heat gained by water and calorimeter = m s w ∆ T + m s cu ∆ T = ( m s w + m s cu ) ( ∆ T ) = ( .
kg × . × J kg – K – + . kg × . × J kg – K – ) ( ° C – ° C) In the steady state heat lost by the aluminium sphere = heat gained by water + heat gained by calorimeter.