📖 generic · 12th TN - English Medium · CHEMISTRY-VOLUME 1 · Page 284question

4. Estimation of sodium hydroxide · Part 2

Chapter 4: Chapter 4 · CHEMISTRY-VOLUME 1

solution V = ml Normality of standard Na CO solution N = . N According to normality equation: According to normality equation: V × N = V × N V N N = V Normality of HCl (link) solution (N ) = ­ N Titration–II ( Unknown NaOH ) Vs (Link HCl) Burette is washed with water, rinsed with HCl solution and filled with same HCl solution up to the zero mark. Exactly ml of unknown NaOH solution is pipetted out into the clean, washed conical flask. To This solution to drops of phenolphthalein indicator is added and titrated against HCl link solution from the burette.

HCl is added drop wise till the pink colour disappears completely. Burette reading is noted and the same procedure is repeated to get concordant values. X organic organic - - - - Titration –II (Link HCl )Vs (Unknown NaOH solution) s.n Volume of Unknown NaOH (ml) Burette readings Concordant value (Volume of HCl) (ml) Initial (ml) Final (ml) Calculation : Volume of Unknown NaOH solution V = ml Normality of Unknown NaOH solution N = ? N Volume of HCl (link) solution V = ml Normality HCl (link) solution N = N According to normality equation: V N = x V x N x V N N = V Normality of Unknown HCl solution N = N Weight calculation: The amount of NaOH dissolved in lit of the solution = (Normality) x (equivalent weight) The amount of NaOH dissolved in ml of the solution = Normality x equivalentweight x = Y × x x g Report : The amount of NaOH dissolved in ml of the solution g Y organic organic - - - -

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