📖 generic · 12th TN - English Medium · CHEMISTRY-VOLUME 1 · Page 275question

II-VOLUMETRIC ANALYSIS

Chapter 8: 7 · CHEMISTRY-VOLUME 1

II-VOLUMETRIC ANALYSIS organic organic - - - - Titration –I (Link KMnO )Vs ( Standard FAS) S.no Volume of standard FAS (ml) Burette readings Concordant value (Volume of KMnO ) (ml) Initial (ml) Final (ml) Calculation : Volume of KMnO (link) solution (V ) = ----------ml Normality KMnO (link) solution (N ) =-----------N Volume of standard FAS solution (V ) = ml Normality of standard FAS solution (N ) = . N According to normality equation: V × N = V × N V N N = V Normality of KMnO (link) solution (N ) = ­ N Titration–II ( Unknown FeSO ) Vs (Link KMnO ) Burette is washed with water, rinsed with KMnO solution and filled with same KMnO solution up to the zero mark. Exactly ml of unknown FeSO solution is pipetted out into the clean, washed conical flask. To this FeSO solution approximately 20ml of 2N sulphuric acid is added.

This mixture is titrated against KMnO Link solution from the burette. KMnO is added drop wise till the appearance of permanent pale pink colour. Burette reading is noted and the same procedure is repeated to get concordant values. X organic organic - - - - Titration –II (Link KMnO )Vs ( Unknown FeSO solution) s.no Volume of Unknown FeSO (ml) Burette readings Concordant value (Volume of KMnO ) (ml) Initial (ml) Final (ml) Calculation : Volume of Unknown FeSO solution V ml Normality of Unknown FeSO solution N ?

N Volume of KMnO (link) solution V ml Normality KMnO (link) solution N X N According to normality equation: V × N = V × N V N N = V N = N The normality of unknown FeSO solution = N Weight calculation: The amount of FeSO dissolved in lit of the solution = (Normality) x (equivalent weight) The amount of FeSO dissolved in ml of the solution = Normality x equivalentweight x N Y g Report : The amount of FeSO dissolved in ml of the solution = g Y organic organic - - - -

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