product. The structure of product “B” is a) Cl CH CH CH b) H C CH CH CH CH Cl c) H C CH C CH Cl d) H C CH CH Cl . Carboxylic acids have higher boiling points than aldehydes, ketones and even alcohols of comparable molecular mass. It is due to their (NEET) a) more extensive association of carboxylic acid via van der Waals force of attraction b) formation of carboxylate ion c) formation of intramolecular H-bonding d) formation of intermolecular H – bonding Short Answer Questions .
How is propanoic acid is prepared starting from (a) an alcohol (b) an alkylhalide (c) an alkene . A Compound (A) with molecular formula C H N on acid hydrolysis gives(B) which reacts with thionylchloride to give compound(C). Benzene reacts with compound (C) in presence of anhydrous AlCl to give compound(D). Compound (D) on reduction with Zn/Hg and Conc.HCl gives (E).
Identify (A), (B), (C), (D) and (E). Write the equations. . Identify X and Y.
CH COCH CH COOC H X Y CH MgBr H O XII U12-Carbonyl XII U12-Carbonyl - - - - . Identify A, B and C benzoic acid PCl A Benzene Anhydrous AlCl B H + C H OH C H MgBr . Identify A, B, C and D ethanoic acid A Pd/BaSO B NaOH D SOCl . An alkene (A) on ozonolysis gives propanone and aldehyde (B).
When (B) is oxidised (C) is obtained. (C) is treated with Br /P gives (D) which on hydrolysis gives (E). When propanone is treated with HCN followed by hydrolysis gives (E). Identify A, B, C, D and E.
. How will you convert benzaldehyde into the following compounds? (i) benzophenone (ii) benzoic acid (iii) α -hydroxyphenylaceticacid. .
What is the action of HCN on (i) propanone (ii) , -dichlorobenzaldehyde. iii) ethanal . A carbonyl compound A having molecular formula C H O forms crystalline precipitate with sodium bisulphite