gas is bubbled through water at K, how many millimoles of N gas would dissolve in litre of water? Assume that N exerts a partial pressure of . bar. Given that Henry’s law constant for N at K is .
k bar. The solubility of gas is related to the mole fraction in aqueous solution. The mole fraction of the gas in the solution is calculated by applying Henry’s law. Thus: x (Nitrogen) = H (nitrogen) K = .987bar , bar = .
× – As litre of water contains . mol of it, therefore if n represents number of moles of N in solution, x (Nitrogen) = mol mol . mol + = . = .
× – ( n in denominator is neglected as it is < < . ) Thus n = . × – × . mol = .