Example 2.3
Chapter 2: Electrochemistry · CHEMISTRY · EN medium
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Electrical work done in one second is equal to electrical potential multiplied by total charge passed. If we want to obtain maximum work from a galvanic cell then charge has to be passed reversibly. The reversible work done by a galvanic cell is equal to decrease in its Gibbs energy and therefore, if the emf of the cell is E and nF is the amount of charge passed and D r G is the Gibbs energy of the reaction, then D r G = – nFE (cell) ( . ) It may be remembered that E (cell) is an intensive parameter but D r G is an extensive thermodynamic property and the value depends on n . Thus, if we write the reaction Zn(s) + Cu + (aq) ¾® Zn + (aq) + Cu(s) ( . )
📖 ncert books class 12 chemistry chapter 2 · Page 10
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Electrical work done in one second is equal to electrical potential multiplied by total charge passed. If we want to obtain maximum work from a galvanic cell then charge has to be passed reversibly. The reversible work done by a galvanic cell is equal to decrease in its Gibbs energy and therefore, if the emf of the cell is E and nF is the amount of charge passed and D r G is the Gibbs energy of the reaction, then D r G = – nFE (cell) ( . ) It may be remembered that E (cell) is an intensive parameter but D r G is an extensive thermodynamic property and the value depends on n .
Thus, if we write the reaction Zn(s) + Cu + (aq) ¾® Zn + (aq) + Cu(s) ( . )
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