Example 2.6 · Part 3 — CHEMISTRY, CBSE Class 12th English Medium | Examozhi

  = . S cm mol – + . S cm mol – = S cm mol – . L m for NaCl, HCl and NaAc are .

, . and . S cm mol – respectively. Calculate L for HAc.

HAc   H Ac   H Cl Ac Na Cl Na       HCl NaAc NaCl  = ( . + . – . ) S cm mol – = .

S cm mol – . The conductivity of .001028 mol L – acetic acid is . × – S cm – . Calculate its dissociation constant if L m for acetic acid is .

S cm mol – . . . Scm 1000cm 001028 mol L L c     = .

S cm mol – a  . Scm mol . Scm mol = . k .

Example 2.6 · Part 3