📖 generic · CBSE Class 12th English Medium · PHYSICS PART-2 · Page 233question

C HAPTER 9

Chapter 8: Chapter 15 · PHYSICS PART-2

C HAPTER . v = – cm. The image is real, inverted and magnified. The size of the image is .

cm. As u  f , v  ; for u < f, image is virtual. . v = .

cm. Magnification = / , i.e., the size of the image is . cm. As u  ; v  f (but never beyond) while m  .

n ga = . ; n wa = . ; n gw = . ; which gives sin r = .

. c i  , where r is the radius (in m) of the largest circle from which light comes out and i c is the critical angle for water-air interface, Area = . m . n  .

and D m for prism in water  10º . R = cm . Here the object is virtual and the image is real. u = + cm (object on right; virtual) (a) f = + cm.

Image is real and at . cm from the lens on its right side. (b) f = – cm. Image is real and at cm from the lens on its right side.

. v = . cm, image is erect and virtual. It is diminished to a size .

cm. As u  , v  f (but never beyond f while m  ). Note that when the object is placed at the focus of the concave lens ( cm), the image is located at . cm (not at infinity as one might wrongly think).

. A diverging lens of focal length cm . (a) v e = – cm and  f e = . cm give u e = – cm; v O = ( – ) cm = cm, f O = u O = – .

cm; Magnifying power = (b) u O = – . cm. Magnifying power = . .

. Angular magnification of the eye-piece for image at cm . ; | | . cm 27cm e u ; v O = .

cm Separation = . cm; Magnifying power =

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