Unit - Thermodynamics Evaluation Yourself . Solution : Given ∆H f CO = - . kJ mol - ∆H f CO = - . kJ mol - ∆H f (H O) = - kJ mol - CO (g) + H (g) → CO(g) + H O(g) ∆H r = ?
∆H r = Σ (∆H f ) products – Σ (∆H f ) reactants ∆H r = [∆H f (CO) + ∆H f (H O)] – [∆H f (CO )+∆H f (H )] ∆H r = [– . + (– )] – [– . + ( )] ∆H r = [– . ] + .
∆H r = . ∆H r = + . kJ mol – . Solution : Given : number of moles of water n g g mol mol − = molar heat capacity of water C P = .
J K – mol – T = C = K T = C = K D H = ? D H = nC P (T – T ) D H = mol × . J mol – K – × ( – ) K D H = 56475 J D H = . kJ .
C H l O g ( ) ( ) CO (g) H O (l) → D U at C = – . kJ Solution : Given T = C = K ; D U = – . kJ mol – D H = ? D H = D U + D n g RT D H = D U + (n p – n r ) RT H .
– . D H = – . kJ mol – . Solution : Given : Mg(S)