📖 generic · 12th TN - English Medium · CHEMISTRY-VOLUME 1 · Page 281question

3. Estimation of oxalic acid · Part 2

Chapter 3: Chapter 3 · CHEMISTRY-VOLUME 1

Concordant value (Volume of KMnO ) (ml) Initial (ml) Final (ml) Calculation : Volume of KMnO (link) solution V ml Normality KMnO (link) solution N ? N Volume of standard FAS solution V ml Normality of standard FAS solution N . N According to normality equation: V N = x V x N N = V N V x Normality KMnO (link) solution N = N Titration–II ( Unknown oxalic acid ) Vs (Link KMnO ) Burette is washed with water, rinsed with KMnO solution and filled with same KMnO solution up to the zero mark. Exactly ml of unknown oxalic acid solution is pipetted out into the clean, washed conical flask.

To this oxalic acid solution approximately 20ml of 2N sulphuric acid is added. This mixture is heated to – C using Bunsen burner and that hot solution is titrated against KMnO Link solution from the burette. KMnO is added drop wise till the appearance of permanent pale pink colour. Burette reading are noted, the same procedure is repeated to get concordant values.

organic organic - - - - Titration –II (Link KMnO )Vs ( Unknown oxalic acid) s.no Volume of Unknown oxalic acid (ml) Burette readings Concordant value (Volume of KMnO ) (ml) Initial (ml) Final (ml) Calculation : Volume of Unknown oxalic acid solution V ml Normality of Unknown oxalic acid solution N = ? N Volume of KMnO (link) solution V = ml Normality KMnO (link) solution N = N According to normality equation: V N = x V x N x V N N = V Normality of Unknown oxalic acid solution N = N Weight calculation: The amount of oxalic acid dissolved in lit of the solution =(Normality) x (equivalent weight) The amount of oxalic acid dissolved in ml of the solution = Y × x x g Report : The amount of oxalic acid dissolved in ml of

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